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Rewind or replace the electric motor

When a motor burns out, the decision is not just the repair price: a rewound motor usually runs a little less efficiently and uses more energy for the rest of its life. Compare the annual cost of each path and find out in how many months the new motor pays for itself.

Pre-sizing and estimating tool: the results do not replace a design, calculation, or report signed by a qualified professional, nor verification against the applicable standards.

VerificationRevision 12/11/2026

Technical responsibility. This calculator is under verification. The reference values and examples are hypothetical, to illustrate the calculation, and are not technical references. The user is responsible for the data entered, the choice of parameters, and the use of the results, and must validate them with a qualified professional before any decision, purchase, application, or construction work.

Engine and use
Option 1: rewind the current motor
Option 2: buy a new high-efficiency motor
Cost of downtime and money

Prices, tariff and efficiencies are entered by you: the starting values are plausible examples for a 30 kW 4-pole motor, not quotes. Use the efficiency from the motor nameplate or catalog at the load it runs at.

Top-up: pumping and motor replacement
Rewind or replace
Return on replacing the motor

The default values are hypothetical, for illustration only. Use the pump curve, the motor nameplate and your utility's tariff.

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—Rewind or buy new?
—

Equivalent annual cost: rewind vs. buy new

How to read: each bar is the total annual cost of keeping the motor running, adding up the investment spread over its useful life (light part) and the energy bill (dark part). Lower is better. A new motor usually costs more to buy and less to run.

Tap the chart to see the values.

Annual cost by hours of use per year

How to read: each line is the annual cost of one option for different hours of operation. The rewound motor starts cheaper and rises faster, because it uses more energy. Where the lines cross, both options cost the same; to the right of the crossing, the new motor pays off. The vertical line is your case.

Tap the chart to see the values.

Accumulated spending over the years

How to read: each line adds up what you have spent since the day of the decision (investment plus energy, without interest). The new motor line starts higher; where it crosses the rewound motor line, the extra investment has paid back (payback). If the crossing comes after the rewound motor's useful life, it is not worth it.

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Side-by-side comparison

Columns: the rewinding option, the new motor option and the difference (new minus rewound). Positive values in the cost difference mean the new motor is more expensive; negative values mean it is cheaper.

What if the data changes?

Drag the controls to simulate data different from what you entered (from 30% less to 30% more) and watch the result change instantly.

Tap the chart to see the values.

Annual cost difference by power, hours, and tariff

Equivalent annual cost of the rewound and new motor for different hours of use per year, with the other data entered.

Step by step with your numbers

The calculation done in steps, with the values you entered.

    —Pump engine: power and replacement
    —

    Engine power by flow

    Power with margin for flows of 20 to 120 m³/h at the head you entered; the dot is your flow.

    Tap the chart to see the values.

    Annual energy: rewound and new

    Annual energy spending with the rewound motor and with the new motor.

    Tap the chart to see the values.

    Return on replacing the motor

    Cash flow: investment in the new motor, net of rewinding, in year 0, and annual energy savings adjusted by the entered tariff and discounted at the TMA.

    The calculation memo gathers this page's inputs, results, equations, assumptions, and references, with fields for project, responsible person, and review. The full report also includes the charts and interpretations, in color. In the print window, choose Save as PDF.

    How to use

    The page has two parts. The first, rewind or replace the electric motor, compares the annual cost of rewinding the current motor with buying a new motor, based on operating hours, the tariff and the cost of each option, with the cumulative spending over the years and a year-by-year table. The second, Top-up: pumping and motor replacement, sizes the motor power from the flow rate, the total head and the pump efficiency, and calculates the payback of the replacement.

    Use the first part to decide whether to repair the current engine and the second to choose the power of the pump engine.

    Hypothetical example (illustrative values)

    Hypothetical values, to understand the calculation. They are not technical or market references.

    Pump of 60 m³/h at 40 m of head, with 60% efficiency and 15% margin. The hydraulic power is 6.54 kW (60 × 40 × 9.81 ÷ 3,600). At the shaft, 6.54 ÷ 0.60 = 10.90 kW. With the margin, 12.54 kW, and the nearest commercial motor is 15 kW.

    Motor replacement: rewinding costs R$ 2,500 and a new motor R$ 4,500, with 92% efficiency versus 78% for the rewound one. With 1,200 h per year and a tariff of R$ 0.90 per kWh, the saving is about R$ 2,297 per year. The difference of R$ 2,000 pays for itself in about 0.9 year.

    Precautions

    • Check the pump curve with the supplier before buying the motor. The actual installation height and pipe losses change the power needed.
    • Efficiencies are reference values. The motor nameplate and a fuel consumption test give the right number for your machine.
    • For the energy cost of other machines, see the diesel consumption per machine hour e o machine hourly cost.

    Method, assumptions, and references

    Equations used

    Top-up, power: hydraulic = Q × H × 9.81 ÷ 3,600; at the shaft = hydraulic ÷ pump efficiency; commercial motor = first catalog value ≥ shaft × (1 + margin)
    Top-up, energy saving: (shaft ÷ rewound efficiency − shaft ÷ new efficiency) × hours per year × tariff; net payback of the rewinding investment
    Electrical energy per year = shaft power × load × hours per year ÷ efficiency; energy cost = energy × tariff
    Rewound efficiency = original efficiency − efficiency loss from rewinding (entered, in percentage points)
    Capital recovery factor CRF(i, N) = i·(1 + i)^N ÷ ((1 + i)^N − 1); if i = 0, CRF = 1/N
    Equivalent annual cost = investment × CRF(i, useful life) + energy cost; rewound investment = rewinding + days stopped × downtime cost; new investment = price + installation − scrap + days stopped × downtime cost
    Payback (months) = 12 × (investment in the new one − investment in the rewound one) ÷ annual energy savings
    Breakeven hours = (annualized capital of new − of rewound) ÷ (power × load × tariff × (1/η rewound − 1/η new)); maximum cost to rewind = (annual cost of new − energy of rewound) ÷ CRF(rewound) − cost of stoppage

    Assumptions and limits

    • The efficiencies you enter apply to the average load you entered and are constant over the year. Motors running at very low or variable load (pumps and fans with a valve or inverter) require an analysis by load profile.
    • The efficiency loss from rewinding is an entered value: it depends on the workshop and the process. The rule of thumb for the cost of rewinding relative to a new motor (50% to 60%) is only a reference, not a standard.
    • Prices, tariff, discount rate and useful lives are entered by the user. Taxes, warranty, risk of new failure, tariff changes or changes in motor price are not included.

    Standards and technical documents

    • IEC 60034-30-1: Rotating electrical machines, efficiency classes of line-operated AC motors (IE code)
    • IEC 60034-2-1: method for determining losses and efficiency of electrical machines
    • Brigham, E. F.; Ehrhardt, M. C. Administração financeira: valor do dinheiro no tempo e custo de capital. Cengage

    Legislation and regulations in Brazil

    • Check with the manufacturer and the distributor the minimum efficiency and safety requirements that apply to the motor and the installation.

    Frequently asked questions

    Is it worth rewinding an electric motor?

    It depends on the size, the hours of use, and the repair price. For small motors with few hours per year, rewinding usually pays off. For large motors that run many hours, energy costs more than repair, and a new high-efficiency motor tends to win. The calculator does this math with your numbers.

    Does rewinding reduce motor efficiency?

    It can get worse. With a well-controlled process, the typical drop is around half to one percentage point; if the old winding is removed without temperature control, it can exceed two points. Ask the workshop for a yield test. Here, the loss is a value you enter.

    What is the rule for rewinding up to 50% or 60% of a new motor?

    It is a rule of thumb: if the repair costs more than half, or 60%, of the price of a new motor, the trend is to buy new. It ignores hours of use and tariff, so the page shows the number as a reference and decides by the equivalent annual cost.

    What is the equivalent annual cost?

    It is the total annual cost of each option: the investment divided by the useful life, plus the cost of money, plus the year’s electricity bill. It lets you compare a motor that lasts 8 years with one that lasts 15 fairly.

    How to read the example result?

    With a 30 kW motor, 75% load, 6,000 hours per year and a tariff of R$ 0.65 per kWh, the old motor had 90.5% efficiency and, once rewound, drops to 89.5%: it uses about 150.8 thousand kWh per year. The new motor (93.6%) uses about 144.2 thousand kWh. Savings are about R$ 4,300 per year, and the new motor's extra investment of R$ 14,200 pays back in about 40 months. On an equivalent annual cost basis, the new motor is about R$ 2,600 per year cheaper.

    What if I have a spare motor?

    If there is a backup motor or another machine to absorb production, the cost of a stoppage is zero and the decision comes down only to repair cost, energy and useful life. If stoppages are costly, the lead time for a new motor and for the workshop becomes very important.

    Can I rely on payback to decide?

    Payback is an estimate based on the values entered. It does not include tariff changes, the risk of a new failure, warranty, or the motor's actual load. Confirm yields and prices with the manufacturer and the workshop, and test more pessimistic scenarios.